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    Bring4th Bring4th Studies L/L Research Channeling Archives 1973.08.x - Hatonn & Oxal

    Thread: 1973.08.x - Hatonn & Oxal


    colorado (Offline)

    Member
    Posts: 62
    Threads: 6
    Joined: Dec 2009
    #3
    12-14-2009, 02:14 AM
    He said the word "power", so it sounds like he meant:

    T^3 / 3 = S^3

    You can write this however you want:

    T^3 = 3 * S^3

    He also said the word "displacement", which makes me think the correct form of the equation is actually the change in each parameter so:

    (T2 - T1)^3 = 3 * (S2-S1)^3

    So by this formula, this is implying the constant 3 has units of [sec]^3/[m]^3 (using standard SI units from physics). I would be interested in hearing a more detailed description of this relationship, and what it actually means.

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    Messages In This Thread
    1973.08.x - Hatonn & Oxal - by ayadew - 09-07-2009, 12:38 PM
    RE: 1973.08.x - Hatonn & Oxal - by Whitefeather - 09-14-2009, 04:21 AM
    RE: 1973.08.x - Hatonn & Oxal - by colorado - 12-14-2009, 02:14 AM
    RE: 1973.08.x - Hatonn & Oxal - by artichoke - 12-16-2009, 08:56 PM
    RE: 1973.08.x - Hatonn & Oxal - by artichoke - 12-17-2009, 04:55 PM
    RE: 1973.08.x - Hatonn & Oxal - by 3D Sunset - 12-18-2009, 12:18 PM
    RE: 1973.08.x - Hatonn & Oxal - by artichoke - 12-18-2009, 04:06 PM
    RE: 1973.08.x - Hatonn & Oxal - by ayadew - 12-19-2009, 05:39 AM
    RE: 1973.08.x - Hatonn & Oxal - by ayadew - 12-18-2009, 01:44 PM
    RE: 1973.08.x - Hatonn & Oxal - by Whitefeather - 01-03-2010, 09:19 PM
    RE: 1973.08.x - Hatonn & Oxal - by ayadew - 01-05-2010, 05:55 PM
    RE: 1973.08.x - Hatonn & Oxal - by Whitefeather - 01-05-2010, 07:15 PM
    RE: 1973.08.x - Hatonn & Oxal - by ayadew - 01-06-2010, 09:21 AM
    RE: 1973.08.x - Hatonn & Oxal - by Whitefeather - 01-06-2010, 02:09 PM

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